advent-of-code-2022/day04/main.hs
2022-12-04 21:56:11 +01:00

55 lines
1.7 KiB
Haskell

-- main.hs as written by me, thuroughly fixed by <https://github.com/h7x4>
main :: IO ()
main = do
file <- readFile "input.txt"
let
pairs :: [((Int, Int), (Int, Int))]
pairs = inputLinesToPairs file
putStrLn "Part 1: "
print $ part1 pairs
putStrLn "Part 2: "
print $ part2 pairs
-- Map each line of input from "1-2,3-4" to ((1,2),(3,4))
inputLinesToPairs :: String -> [((Int, Int), (Int, Int))]
inputLinesToPairs input = result
where
stringpairs :: [[String]]
stringpairs = map (splitWhen (==',')) $ lines input
parseRange :: String -> (Int, Int)
parseRange pair = (read first, read second)
where
(first:second:_) = splitWhen (=='-') pair
result :: [((Int, Int), (Int, Int))]
result = map (\x -> (head x, last x)) $ map (map parseRange) stringpairs
part1 :: [((Int, Int), (Int, Int))] -> Int
part1 = length . filter (uncurry rangeIsContained)
part2 :: [((Int, Int), (Int, Int))] -> Int
part2 = length . filter (uncurry rangeOverlaps)
-- True if any part of the two ranges overlap
rangeOverlaps :: (Int, Int) -> (Int, Int) -> Bool
rangeOverlaps (lo1, hi1) (lo2, hi2) = rangeIsContained (lo1, lo1) (lo2, hi2)
|| (lo2 >= lo1 && lo2 <= hi1)
|| (hi2 >= lo1 && hi2 <= hi1)
-- True if the first range is entirely contained in the second range, or vice versa
rangeIsContained :: (Int, Int) -> (Int, Int) -> Bool
rangeIsContained (lo1, hi1) (lo2, hi2) = (lo1 <= lo2 && hi1 >= hi2)
|| (lo1 >= lo2 && hi1 <= hi2)
-- Modified from Prelude.words
splitWhen :: (Char -> Bool) -> String -> [String]
splitWhen p s = case dropWhile p s of
"" -> []
s' -> w : splitWhen p s''
where (w, s'') = break p s'